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(x*(ln(3*x^2)/5)+1)'The calculation above is a derivative of the function f (x)
(x*(ln(3*x^2)/5))'+(1)'
(x)'*(ln(3*x^2)/5)+x*(ln(3*x^2)/5)'+(1)'
1*(ln(3*x^2)/5)+x*(ln(3*x^2)/5)'+(1)'
1*(ln(3*x^2)/5)+x*(((ln(3*x^2))'*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*(((1/(3*x^2))*(3*x^2)'*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*(((1/(3*x^2))*((3)'*x^2+3*(x^2)')*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*(((1/(3*x^2))*(0*x^2+3*(x^2)')*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*(((1/(3*x^2))*(0*x^2+3*2*x^(2-1))*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*(((1/(3*x^2))*(0*x^2+3*2*x)*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*((2*x^-1*5-(ln(3*x^2)*(5)'))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*((2*x^-1*5-(ln(3*x^2)*0))/(5^2))+(1)'
1*(ln(3*x^2)/5)+x*((2*x^-1)/5)+(1)'
ln(3*x^2)/5+0+2/5
ln(3*x^2)/5+2/5
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